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-12x^2-11x+10=0
a = -12; b = -11; c = +10;
Δ = b2-4ac
Δ = -112-4·(-12)·10
Δ = 601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{601}}{2*-12}=\frac{11-\sqrt{601}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{601}}{2*-12}=\frac{11+\sqrt{601}}{-24} $
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